tag:blogger.com,1999:blog-9083432202110501770.post2985822042060473971..comments2024-02-25T20:39:02.181-08:00Comments on A physics teacher: Homogeneity of equationsJohn Tanhttp://www.blogger.com/profile/00706551494379271443noreply@blogger.comBlogger5125tag:blogger.com,1999:blog-9083432202110501770.post-16671085554576391262014-09-11T03:32:20.140-07:002014-09-11T03:32:20.140-07:00is the equation v=wr in circular motion homogeneou...is the equation v=wr in circular motion homogeneous? as w is in rads-1, r is in m and v is in ms-1<br />ThanksAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-9083432202110501770.post-53046657357352008832014-04-30T18:39:37.319-07:002014-04-30T18:39:37.319-07:00s is displacement, not time. So it is in metres.s is displacement, not time. So it is in metres.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-9083432202110501770.post-32897831298866788032014-03-17T07:06:54.284-07:002014-03-17T07:06:54.284-07:00is the unit of s, m. I believe it's s.is the unit of s, m. I believe it's s. Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-9083432202110501770.post-31503485334920991622013-08-10T01:00:58.628-07:002013-08-10T01:00:58.628-07:00v^2= u^2+2as. 2 is a constant so its not counted i...v^2= u^2+2as. 2 is a constant so its not counted it.<br />(ms^-1)^2= (ms^-1)^2 + (ms^-2)(m)<br />(m^2s^-2) = m^2s^-2 + m^2s^-2. They are all the same, right? Hope I helped you.Chanhttps://www.blogger.com/profile/09980029373914183435noreply@blogger.comtag:blogger.com,1999:blog-9083432202110501770.post-73246316608122897812013-05-19T11:31:18.141-07:002013-05-19T11:31:18.141-07:00I understood the first one completely seems simple...I understood the first one completely seems simple enough but on the second I could only get as far as:<br /><br /><br />v2 = u2 + 2as<br /><br />(ms-1)2 = (ms-1)2 + 2( m/s2 * m)<br /><br />Think you can help?<br />Thanks in advance, great page by the way !Anonymousnoreply@blogger.com